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14m^2-12m=0
a = 14; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·14·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*14}=\frac{0}{28} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*14}=\frac{24}{28} =6/7 $
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